1869 Rhode Island gubernatorial election

1869 Rhode Island gubernatorial election

← 1868 April 7, 1869 1870 →

Nominee Seth Padelford Lyman Pierce Party Republican Democratic Popular vote 7,359 3,390 Percentage 68.46% 31.54%

County results Padelford:      60–70%      70–80%      80–90%

Governor before election Ambrose Burnside Republican Elected Governor Seth Padelford Republican

Elections in Rhode Island
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Ballot measures 2020 Question 1
Providence Mayoral elections 1998 2002 2006 2010 2014 2018 2022
v t e

The 1869 Rhode Island gubernatorial election took place on April 7, 1869, in order to elect the governor of Rhode Island.^[1] Republican candidate and incumbent governor Seth Padelford won his first one-year term as governor^[2] against Democratic candidate Lyman Pierce.^[3]