1881 Iowa Senate election

1881 Iowa Senate election

← 1879 October 11, 1881 1883 →

25 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party Third party
 
Party Republican Democratic Greenback
Last election 41 7 2
Seats after 45 2 2
Seat change Increase4 Decrease5 Steady

  Fourth party
 
Party Independent
Last election 0
Seats after 1
Seat change Increase1

In the 1881 Iowa State Senate elections Iowa voters elected state senators to serve in the nineteenth Iowa General Assembly. Elections were held in 25 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

The general election took place on October 11, 1881.[1]

Following the previous election, Republicans had control of the Iowa Senate with 41 seats to Democrats' seven seats and two Greenbackers.

To claim control of the chamber from Republicans, the Democrats needed to net 19 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1881 general election with the balance of power shifting to Republicans holding 45 seats, Democrats having two seats, two Greenbackers, and one Independent (a net gain of 4 seats for Republicans and 1 Independent seat).

  1. ^ "Members of the Senate, 1882" (PDF). Iowa Official Register. Retrieved June 27, 2021.