1883 Iowa Senate election

1883 Iowa Senate election

← 1881 October 9, 1883 1885 →

29 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party Third party
 
Party Republican Democratic Greenback
Last election 45 2 2
Seats after 39 11 0
Seat change Decrease6 Increase9 Decrease2

  Fourth party
 
Party Independent
Last election 1
Seats after 0
Seat change Decrease1

In the 1883 Iowa State Senate elections Iowa voters elected state senators to serve in the twentieth Iowa General Assembly. Elections were held in 29 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

The general election took place on October 9, 1883.[1]

Following the previous election, Republicans had control of the Iowa Senate with 45 seats to Democrats' two seats, two Greenbackers, and one Independent.

To claim control of the chamber from Republicans, the Democrats needed to net 24 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1883 general election with the balance of power shifting to Republicans holding 39 seats and Democrats having 11 seats (a net gain of 9 seats for Democrats).

  1. ^ "General Assembly: 20 (01/14/1884 - 01/10/1886)". Iowa Legislature. Retrieved June 27, 2021.