1892 World Series

1892 World Series
NL: Boston Beaneaters (5–0–1)
NL: Cleveland Spiders (0–5–1)
Pre-modern World Series
Boston Beaneaters
Cleveland Spiders

The 1892 World Series followed the first split season in National League history, with the first-half champion Boston Beaneaters (102–48) playing the second-half champion Cleveland Spiders (93–56) in a best-of-nine postseason series to determine the overall champion of the 1892 baseball season. After the first game ended in a 0–0 tie due to darkness, Boston won the next five games to win the championship.

Contemporary newspaper reports referred to the games as the "world's championship series"[1] or "World's Series".[2] This was the last of the pre-modern-era World Series, and followed similar annual postseason competitions held from 1884 to 1890 between the champions of the National League and the American Association (which collapsed after the 1891 season). Later, the Temple Cup would be awarded to the winner of an annual postseason series between National League teams, from 1894 to 1897.

  1. ^ "Base Ball Briefs". The Pittsburgh Press. October 20, 1892. p. 5. Retrieved April 5, 2021 – via newspapers.com.
  2. ^ "World's Series: Boston Gets First Blood". The Cincinnati Enquirer. October 19, 1892. p. 2. Retrieved April 5, 2021 – via newspapers.com.