1895 Iowa Senate election

1895 Iowa Senate election

← 1893 November 5, 1895 1897 →

31 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 34 16
Seats after 43 7
Seat change Increase9 Decrease9

In the 1895 Iowa State Senate elections Iowa voters elected state senators to serve in the twenty-sixth Iowa General Assembly. Elections were held in 31 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

A statewide map of the 50 state Senate districts in the 1895 elections is provided by the Iowa General Assembly here.

The general election took place on November 5, 1895.[1]

Following the previous election, Republicans had control of the Iowa Senate with 34 seats to Democrats' 16 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 10 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1895 general election with the balance of power shifting to Republicans holding 43 seats and Democrats having 7 seats (a net gain of 9 seats for Republicans).

  1. ^ "The Twenty-Sixth General Assembly. SENATE" (PDF). Iowa Official Register. Retrieved June 25, 2021.