1926 Tour de France

1926 Tour de France
Map of France with 17 cities shown, connected by red lines. Most of the shown cities are close to the border, except the ones labeled "Dijon" and "Paris".
Route of the 1926 Tour de France followed counterclockwise, starting in Evian,
going counter-clockwise around France, and then to Paris
Race details
Dates20 June – 18 July 1926
Stages17
Distance5,745 km (3,570 mi)
Winning time238h 44' 25"
Results
Winner  Lucien Buysse (BEL) (Automoto–Hutchinson)
  Second  Nicolas Frantz (LUX) (Alcyon–Dunlop)
  Third  Bartolomeo Aymo (ITA) (Alcyon–Dunlop)
← 1925
1927 →

The 1926 Tour de France was the 20th edition of the Tour de France, taking place from 20 June to 18 July. It consisted of 17 stages with a total distance of 5745 km, ridden at an average speed of 24.064 km/h.

The longest tour in history,[1] the route traced closely the borders of France. It was the first time that the race started outside Paris;[1] in this way riders were forced to climb the mountains in the east of the country twice, once at the beginning of the race, and again at the end.[2] The race was won by Belgian cyclist Lucien Buysse.

  1. ^ a b Augendre 2016, p. 108.
  2. ^ Tom James (15 August 2003). "1926: The longest Tour". VeloArchive. Retrieved 21 September 2009.