1930 Iowa Senate election

1930 Iowa Senate election

← 1928 November 4, 1930 1932 →

21 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 48 2
Seats after 44 6
Seat change Decrease4 Increase4

Results
     Democratic gain      Republican gain
     Republican hold

The 1930 Iowa State Senate elections took place as part of the biennial 1930 United States elections. Iowa voters elected state senators in 21 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

A statewide map of the 50 state Senate districts in the 1930 elections is provided by the Iowa General Assembly here.

The primary election on June 2, 1930, determined which candidates appeared on the November 4, 1930 general election ballot.[1][2]

Following the previous election, Republicans had control of the Iowa state Senate with 48 seats to Democrats' 2 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 24 Senate seats.[a]

Republicans maintained control of the Iowa State Senate following the 1930 general election with the balance of power shifting to Republicans holding 44 seats and Democrats having 6 seats (a net gain of 4 seats for Democrats).

  1. ^ "Primary Election 1930 For State Senator" (PDF). Iowa Official Register. Retrieved June 29, 2020.
  2. ^ "General Election 1930 For State Senator" (PDF). Iowa Official Register. Retrieved June 29, 2020.


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