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30 out of 50 seats in the Iowa State Senate 26 seats needed for a majority | |||||||||||||||||||
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Elections in Iowa |
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The 1944 Iowa State Senate elections took place as part of the biennial 1944 United States elections. Iowa voters elected state senators in 30 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.
The Iowa General Assembly provides statewide maps of each district. To compare the effect of the 1944 redistricting process on the location of each district, contrast the previous map with the map used for 1944 elections.
The primary election on June 5, 1944, determined which candidates appeared on the November 7, 1944 general election ballot.[1][2]
Following the previous election, Republicans had control of the Iowa state Senate with 45 seats to Democrats' 5 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 21 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1944 general election with the balance of power remaining unchanged with Republicans holding 45 seats and Democrats having 5 seats.