1948 Davis Cup

1948 Davis Cup
Details
Duration22 April – 6 September 1948
Edition37th
Teams29
Champion
Winning nation United States
1947
1949

The 1948 Davis Cup was the 37th edition of the most important tournament between national teams in men's tennis. 25 teams entered the Europe Zone, and four teams entered the America Zone. Pakistan and Turkey made their first appearances in the competition.

Australia defeated Mexico in the America Zone final, and Czechoslovakia defeated Sweden in the Europe Zone final. Australia defeated Czechoslovakia in the Inter-Zonal play-off, but fell to defending champions the United States in the Challenge Round. The championship was played at the West Side Tennis Club in Forest Hills, New York, United States on 4–6 September.[1][2][3]

  1. ^ Bud Collins (2010). The Bud Collins History of Tennis (2nd ed.). [New York]: New Chapter Press. pp. 495–496, 499. ISBN 978-0942257700.
  2. ^ Max Robertson (1974). The Encyclopedia of Tennis. London: Allen & Unwin. p. 384. ISBN 0047960426.
  3. ^ Cite error: The named reference Challenge was invoked but never defined (see the help page).