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29 out of 50 seats in the Iowa State Senate 26 seats needed for a majority | |||||||||||||||||||||||||
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Elections in Iowa |
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The 1956 Iowa State Senate elections took place as part of the biennial 1956 United States elections. Iowa voters elected state senators in 29 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.
A statewide map of the 50 state Senate districts in the year 1956 is provided by the Iowa General Assembly here.
The primary election on June 4, 1956, determined which candidates appeared on the November 6, 1956 general election ballot.[1][2]
Following the previous election, Republicans had control of the Iowa state Senate with 44 seats to Democrats' 6 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 20 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1956 general election with the balance of power shifting to Republicans holding 40 seats and Democrats having 10 seats (a net gain of 4 seats for Democrats).