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39 out of 59 seats in the Iowa State Senate 30 seats needed for a majority | |||||||||||||||||||||||||
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Elections in Iowa |
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The 1964 Iowa State Senate elections took place as part of the biennial 1964 United States elections. Iowa voters elected state senators in 39 of the state senate's 59 districts. At that time, the Iowa Senate still had several multi-member districts. State senators serve four-year terms in the Iowa State Senate.
The Iowa Senate was expanded from 50 to 59 members and new district maps were drawn for the 1964 election. The Iowa General Assembly provides statewide maps of each district. To compare the effect of the 1964 redistricting process on the location of each district, contrast the previous map with the map used for 1964 elections.
The primary election on June 1, 1964, determined which candidates appeared on the November 3, 1964 general election ballot.[2][3]
Following the previous election, Republicans had control of the Iowa state Senate with 38 seats to Democrats' 12 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 18 Senate seats.
Democrats flipped control of the Iowa State Senate following the 1964 general election with the balance of power shifting to Democrats holding 34 seats and Republicans having 25 seats (a net gain of 22 seats for Democrats and net loss of 13 seats for Republicans).[a]
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