| Copa de Campeones Concacaf | |
|---|---|
| Tournament details | |
| Dates | 25 April – 30 September |
| Teams | 10 (from 9 associations) |
| Final positions | |
| Champions |  Cruz Azul |
| Runners-up |  Comunicaciones |
| Third place |  Saprissa |
| Tournament statistics | |
| Matches played | 18 |
| Goals scored | 53 (2.94 per match) |
← 1968 1970 → | |
The 1969 CONCACAF Champions' Cup was the 5th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's football club champion in the CONCACAF region.
The tournament was played by 10 teams of 9 nations: Netherlands Antilles, Bermuda, El Salvador, Haiti, Guatemala, Honduras, Mexico, Nicaragua, Costa Rica. It was played from 25 April to 30 September 1969 under the home/away match system and for the first time, the teams were not split into zones, playing in a straight round system.[1][2]
Cruz Azul from Mexico won the final after beating Guatemalan club Comunicaciones 1–0 in the second leg,[3] becoming CONCACAF champion for the first time in its history.[1][4]
- ^ a b Copa Concacaf 1969 by Jim Goloboy and Karel Stokkermans on the RSSSF
- ^ Campeones 1969 on Footbase
- ^ Comunicaciones en la Concacaf
- ^ "Cruz Azul Campeón de la Concacaf 1969" on Reino Azul (blogsite), 7 Mar 2014