| Tournament details | |
|---|---|
| Dates | October 5–23, 1993[1] |
| Teams | 4 |
| Final positions | |
| Champions | Toronto Blue Jays (2nd title) |
| Runner-up | Philadelphia Phillies (5th World Series appearance) |
| Tournament statistics | |
| MVP | Paul Molitor (TOR) |
The 1993 Major League Baseball postseason was the playoff tournament of Major League Baseball for the 1993 season. The winners of each division advance to the postseason and face each other in a League Championship Series to determine the pennant winners that face each other in the World Series. This was the last edition of the postseason to feature only two rounds, with only division champions qualifying. After the 1994–95 Major League Baseball strike, the playoffs were expanded to include a wild card team and a new League Division Series for the 1995 postseason.
The Toronto Blue Jays and Atlanta Braves both returned to the postseason for the third year in a row, while the Chicago White Sox and Philadelphia Phillies returned for the first time in a decade. This would be the last appearance for the Phillies until 2007, as well as Toronto's last appearance until 2015.
This was the last edition of the postseason until 2008 to not feature the New York Yankees, who would make thirteen straight postseason appearances from 1995 to 2007. It also marked the second time in three years that the postseason did not feature a team from California. To date, this is the last postseason to not feature either the New York Yankees or the Los Angeles Dodgers.
The playoffs began on October 5, 1993, and concluded on October 23, 1993, with the Blue Jays defeating the Phillies in six games in the 1993 World Series. The Blue Jays repeated as World Series champions, becoming the seventh franchise in MLB history to win back-to-back championships.[2]