Cleveland, Utah | |
|---|---|
 Cleveland Post Office, February 2019 | |
 Location in Emery County and the state of Utah | |
 Location of Utah in the United States | |
| Coordinates: 39°20′53″N 110°51′19″W / 39.34806°N 110.85528°W | |
| Country | United States |
| State | Utah |
| County | Emery |
| Settled | 1885 |
| Named for | Grover Cleveland |
| Area | |
| • Total | 0.86 sq mi (2.24 km2) |
| • Land | 0.86 sq mi (2.24 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 5,722 ft (1,744 m) |
| Population (2010) | |
| • Total | 464 |
| • Estimate (2019)[2] | 440 |
| • Density | 508.67/sq mi (196.39/km2) |
| Time zone | UTC-7 (Mountain (MST)) |
| • Summer (DST) | UTC-6 (MDT) |
| ZIP code | 84518 |
| Area code | 435 |
| FIPS code | 49-14070[3] |
| GNIS feature ID | 1426712[4] |
Cleveland is a town in Emery County, Utah, United States. As of the 2010 census, the town population was 464,[5] down from 508 at the 2000 census.
- ^ "2019 U.S. Gazetteer Files". United States Census Bureau. Retrieved August 7, 2020.
- ^ Cite error: The named reference
USCensusEst2019CenPopScriptOnlyDirtyFixDoNotUsewas invoked but never defined (see the help page). - ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "Geographic Identifiers: 2010 Census Summary File 1 (G001): Cleveland town, Utah". American Factfinder. U.S. Census Bureau. Archived from the original on February 13, 2020. Retrieved March 31, 2016.