Town of Delafield, Wisconsin | |
|---|---|
,_Wisconsin&sq=Envato&lang=en&file=File:Delafield_(1).jpg) Town hall | |
,_Wisconsin&sq=Envato&lang=en&file=File:Waukesha_County_Wisconsin_incorporated_and_unincorporated_areas_Delafield_(town)_highlighted.svg) Location in Waukesha County and the state of Wisconsin. | |
| Coordinates: 43°3′29″N 88°20′30″W / 43.05806°N 88.34167°W | |
| Country |  United States |
| State |  Wisconsin |
| County | Waukesha |
| Area | |
• Total | 20.7 sq mi (53.7 km2) |
| • Land | 18.6 sq mi (48.3 km2) |
| • Water | 2.1 sq mi (5.5 km2) |
| Elevation | 981 ft (299 m) |
| Population (2020) | |
• Total | 8,095 |
| • Density | 419.7/sq mi (162.1/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| Area code | 262 |
| FIPS code | 55-19425[2] |
| GNIS feature ID | 1583067[1] |
The Town of Delafield is located in Waukesha County, Wisconsin, United States. The population was 8,095 at the 2020 census. The City of Delafield is adjacent to the town. The unincorporated community of Buena Vista is located in the town.
- ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.