Harlan, Iowa | |
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Coordinates: 41°38′58″N 95°19′36″W / 41.64944°N 95.32667°W | |
Country | United States |
State | Iowa |
County | Shelby |
Area | |
• Total | 4.42 sq mi (11.45 km2) |
• Land | 4.42 sq mi (11.45 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 1,273 ft (388 m) |
Population (2020) | |
• Total | 4,893 |
• Density | 1,107.26/sq mi (427.48/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP codes | 51537, 51593 |
Area code | 712 |
FIPS code | 19-34500 |
GNIS feature ID | 468007[2] |
Website | www |
Harlan is a city and the county seat of Shelby County, Iowa, along the West Nishnabotna River. The population was 4,893 at the time of the 2020 census.[3][4]