 Jost Van Dyke | |
 The location of Jost Van Dyke within the British Virgin Islands | |
  Jost Van Dyke  Jost Van Dyke | |
| Geography | |
|---|---|
| Location | Caribbean Sea |
| Coordinates | 18°27′N 64°45′W / 18.450°N 64.750°W |
| Archipelago | Virgin Islands |
| Area | 8 km2 (3.1 sq mi) |
| Highest point | Majohnny Hill at 321 meters (1054 ft) |
| Administration | |
| British Overseas Territory | British Virgin Islands |
| Demographics | |
| Population | 298 (2010)[1] |
| Additional information | |
| Time zone | |
| ISO code | VG |
Jost Van Dyke (/ˈjoʊst væn ˈdaɪk/;[2] sometimes colloquially referred to as JVD or Jost) is the smallest of the four main islands of the British Virgin Islands, measuring roughly 8 square kilometres (3 square miles). It rests in the northern portion of the archipelago of the Virgin Islands, located in the Atlantic Ocean and Caribbean Sea. Jost Van Dyke lies about 8 km (5 mi) to the northwest of Tortola and 8 km (5 mi) to the north of Saint John, U.S. Virgin Islands. Little Jost Van Dyke lies off its eastern end.
Like many of the neighboring islands, it is volcanic in origin and mountainous. The highest point on the island is Majohnny Hill at 321 m (1,053 ft).
- ^ "Virgin Islands 2010 Population and Housing Census Report" (PDF). p. 6. Retrieved 7 January 2019.
- ^ That is, beginning with a Y sound and rhyming with 'host'.