Leavittsburg, Ohio

Leavittsburg, Ohio
Census-designated place
Location of Leavittsburg in Trumbull County within the state of Ohio
Location of Leavittsburg in Trumbull County within the state of Ohio
Coordinates: 41°14′52″N 80°52′37″W / 41.24778°N 80.87694°W / 41.24778; -80.87694
CountryUnited States
StateOhio
CountyTrumbull
TownshipWarren
Area
[1]
 • Total1.56 sq mi (4.03 km2)
 • Land1.48 sq mi (3.84 km2)
 • Water0.07 sq mi (0.19 km2)
Elevation
[2]
909 ft (277 m)
Population
 (2020)
 • Total1,571
 • Density1,058.63/sq mi (408.86/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
44430
Area code(s)234/330
FIPS code39-42308[3]
GNIS feature ID2393095[2]

Leavittsburg (/ˈlɛvɪtsbɜːrɡ/ LEV-its-burg[4]) is a census-designated place in Trumbull County, Ohio, United States. The population was 1,571 at the 2020 census. Located directly west of Warren, Ohio, it is part of the Youngstown–Warren metropolitan area.

  1. ^ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
  2. ^ a b U.S. Geological Survey Geographic Names Information System: Leavittsburg, Ohio
  3. ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  4. ^ "E.W. Scripps School of Journalism Ohio Pronunciation Guide | Ohio University". www.ohio.edu. Ohio University. 2016. Retrieved August 29, 2023.