Nevada, Ohio | |
|---|---|
 North Main Street downtown | |
 Location of Nevada, Ohio | |
 Location of Nevada in Wyandot County | |
| Coordinates: 40°49′07″N 83°07′42″W / 40.81861°N 83.12833°W | |
| Country | United States |
| State | Ohio |
| County | Wyandot |
| Township | Antrim, Eden |
| Area | |
| • Total | 1.03 sq mi (2.66 km2) |
| • Land | 1.03 sq mi (2.66 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 929 ft (283 m) |
| Population (2020) | |
| • Total | 706 |
| • Density | 688.11/sq mi (265.72/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 44849 |
| Area code | 740 |
| FIPS code | 39-53942[3] |
| GNIS feature ID | 2399447[2] |
Nevada (/nɪˈveɪdə/ niv-AY-də) is a village in Wyandot County, Ohio, United States. The population was 706 at the 2020 census.
- ^ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
- ^ a b U.S. Geological Survey Geographic Names Information System: Nevada, Ohio
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.