Oxford, Indiana | |
|---|---|
 East Smith Street on the town square with the historic 1915 Masonic building. | |
 Location of Oxford in Benton County, Indiana. | |
  Oxford, Indiana Oxford's location in Benton County | |
| Coordinates: 40°31′17″N 87°14′59″W / 40.52139°N 87.24972°W | |
| Country | United States |
| State | Indiana |
| County | Benton |
| Township | Oak Grove |
| Established | 1843 |
| Area | |
| • Total | 0.55 sq mi (1.42 km2) |
| • Land | 0.55 sq mi (1.42 km2) |
| • Water | 0.00 sq mi (0.00 km2) 0% |
| Elevation | 735 ft (224 m) |
| Population (2020) | |
| • Total | 1,165 |
| • Density | 2,125.91/sq mi (821.43/km2) |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 47971 |
| Area code | 765 |
| FIPS code | 18-57546[3] |
| GNIS feature ID | 2396844[2] |
Oxford is a town in Oak Grove Township, Benton County, Indiana. The population was 1,162 at the 2010 census. It is part of the Lafayette, Indiana, Metropolitan Statistical Area.
- ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ^ a b U.S. Geological Survey Geographic Names Information System: Oxford, Indiana
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.