Country (sports) | Canada |
---|---|
Residence | Toronto, Canada Tampa, Florida, United States |
Born | North York, Ontario, Canada | June 15, 1988
Height | 1.83 m (6 ft 0 in) |
Turned pro | 2007 |
Plays | Right-handed (two-handed backhand) |
Prize money | US$1,729,767 |
Singles | |
Career record | 19–45 |
Career titles | 0 |
Highest ranking | No. 110 (25 June 2018)[1] |
Grand Slam singles results | |
Australian Open | 1R (2009, 2017, 2018) |
French Open | 1R (2009, 2014, 2018) |
Wimbledon | 1R (2018) |
US Open | 2R (2010) |
Doubles | |
Career record | 3–7 |
Career titles | 0 |
Highest ranking | No. 123 (December 10, 2018) |
Grand Slam doubles results | |
Wimbledon | Q1 (2017, 2018) |
Team competitions | |
Davis Cup | 1R (2014) |
Last updated on: 27 February 2023. |
Peter Polansky (/pəˈlænski/ pə-LAN-skee;[2] born June 15, 1988) is a Canadian professional tennis player of Czech origin.[3] He was Canada's top singles player from June 21, 2010, until January 17, 2011, in the ATP rankings. He was also Canada's No. 2 from August 4, 2008, until June 21, 2010, with the exception of one week. In 2018, he became the first player in the Open Era to qualify for all four Grand Slam tournaments as a lucky loser within the same calendar year.[4]