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Ramapo, New York | |
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Coordinates: 41°7′19″N 74°5′0″W / 41.12194°N 74.08333°W | |
Country | United States |
State | New York |
County | Rockland |
Government | |
• Supervisor | Michael Specht (D) |
Area | |
• Total | 61.84 sq mi (160.16 km2) |
• Land | 61.14 sq mi (158.35 km2) |
• Water | 0.70 sq mi (1.80 km2) |
Elevation | 371 ft (113 m) |
Population (2020) | |
• Total | 148,919 |
• Density | 2,400/sq mi (930/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 10901, 10952, 10977, 10970, 10965, 10974 |
Area code | 845 |
FIPS code | 36-60510 |
GNIS ID | 0979406 |
Website | ramapo.org |
Ramapo is a town in Rockland County, New York, United States. It was originally formed as New Hampstead, in 1791, and became Ramapo in 1828.[2] It shares its name with the Ramapo River. As of the 2020 census, Ramapo had a total population of 148,919, making it the most populous town in New York outside of Long Island. If all towns in New York were cities, Ramapo would be the 12th-largest city in the state of New York.
The town's name, recorded variously as Ramopuck, Ramapock, or Ramapough, is of Lenape origin, meaning either "sweet water" or "slanting rocks". Early maps referred to Ramapo as Ramepog (1695), Ramepogh (1711), and Ramapog (1775).[3]
The town is located south of Haverstraw and west of Clarkstown and Orangetown.