Robert Howe (tennis)

Bob Howe
Full nameRobert Neville Howe
Country (sports) Australia
Born(1925-08-03)3 August 1925
Sydney, NSW, Australia
Died30 November 2004(2004-11-30) (aged 79)
Santa Ana, California, US
Height1.77 m (5 ft 10 in)
Turned pro1968 (amateur from 1949)
Retired1971
PlaysRight-handed (two-handed backhand)[1]
Singles
Career record500-369
Career titles29
Grand Slam singles results
Australian OpenQF (1958, 1963)
French Open3R (1957)
Wimbledon4R (1956, 1962, 1965)
US Open4R (1957)
Doubles
Career record208–94
Career titles18
Highest rankingNo. 12 (30 August 1977)
Grand Slam doubles results
Australian OpenF (1959)
French OpenF (1958, 1961)
WimbledonSF (1956, 1957)
Mixed doubles
Grand Slam mixed doubles results
Australian OpenW (1958)
French OpenW (1960, 1962)
WimbledonW (1958)

Robert (Bob) Howe (3 August 1925 – 30 November 2004)[2] was an Australian tennis player. Although he won 29 singles titles, his main successes were achieved in the doubles competition. He won four mixed doubles Grand Slam titles, including the Wimbledon mixed doubles championship in 1958.[3]

  1. ^ Sutton Tennis & Squash Club
  2. ^ Tennis Archives biography
  3. ^ "History – Rolls of Honour – Mixed Doubles Finals 1913–2008". wimbledon.org. Archived from the original on 24 November 2010. Retrieved 16 November 2008.