Seymour, Connecticut

Seymour, Connecticut
Town of Seymour
Welcome to Seymour sign
Welcome to Seymour sign
Official seal of Seymour, Connecticut
Motto(s): 
"Seymour, A Nice Place to Visit....A Better Place to Live"[1]
Seymour's location within New Haven County and Connecticut
Map
Map
Map
Coordinates: 41°23′03″N 73°05′13″W / 41.38417°N 73.08694°W / 41.38417; -73.08694
Country United States
U.S. state Connecticut
CountyNew Haven
RegionNaugatuck Valley
Incorporated1850
Government
 • TypeSelectman-town meeting
 • First SelectwomanAnnmarie Drugonis (R)
 • SelectmenTrisha Danka (R)
Al Bruno (R)
Robert Findley (R)
Patrick Lombardi (R)
Chris Bowen (D)
Robert VanEgghen (D)
Area
 • Total15.0 sq mi (38.8 km2)
 • Land14.6 sq mi (37.7 km2)
 • Water0.4 sq mi (1.0 km2)
Elevation
387 ft (118 m)
Population
 (2020)
 • Total16,748
 • Density1,100/sq mi (430/km2)
Time zoneUTC-5 (Eastern)
 • Summer (DST)UTC-4 (Eastern)
ZIP code
06483
Area code(s)203/475
FIPS code09-67610
GNIS feature ID0213502
Websitewww.seymourct.org

Seymour is a town located in New Haven County, Connecticut, United States. The town is part of the Naugatuck Valley Planning Region. The population was 16,748 at the 2020 census.[2] Seymour is bordered by the towns of Oxford and Beacon Falls to the north, Bethany and Woodbridge to the east, Ansonia and Derby to the south, and Shelton to the west.

  1. ^ "Official Town of Seymour Connecticut". Official Town of Seymour Connecticut. Retrieved September 22, 2012.
  2. ^ "Census - Geography Profile: Seymour town, New Haven County, Connecticut". United States Census Bureau. Retrieved December 21, 2021.