y = 9 − x 2 9 − x 2 − 1 ; x = 9 − y 2 9 − y 2 − 1 {\displaystyle y={\frac {\sqrt {9-x^{2}}}{\sqrt {9-x^{2}}}}-1;x={\frac {\sqrt {9-y^{2}}}{\sqrt {9-y^{2}}}}-1} ( x ± 2 ) 2 + ( y ± 2 ) 2 = 1.5 2 , x ∈ ( − 3 , 3 ) {\displaystyle (x\pm 2)^{2}+(y\pm 2)^{2}=1.5^{2},x\in (-3,3)} So what if I'm a geek :)
No goal is unreachable, no effort is futile!
What is wrong with this picture? (answer)
