1832 United States presidential election in Rhode Island

1832 United States presidential election in Rhode Island

← 1828 November 2 – December 5, 1832 1836 →

Nominee Henry Clay Andrew Jackson Party National Republican Democratic Home state Kentucky Tennessee Running mate John Sergeant Martin Van Buren Electoral vote 4 0 Popular vote 2,810 2,126 Percentage 56.93% 43.07%

County Results Clay   40-50%   50-60% Jackson   50-60%

Elections in Rhode Island
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Ballot measures 2020 Question 1
Providence Mayoral elections 1998 2002 2006 2010 2014 2018 2022
v t e

The 1832 United States presidential election in Rhode Island took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Rhode Island voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Rhode Island by a margin of 13.86%.