1840 United States presidential election in Kentucky

1840 United States presidential election in Kentucky
← 1836 October 30 - December 2, 1840 1844 →
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 15 0
Popular vote 58,488 32,616
Percentage 64.20% 35.80%

County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

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The 1840 United States presidential election in Kentucky took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Kentucky voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Kentucky by a margin of 28.4%.

With 64.20% of the popular vote, Kentucky would prove to be Harrison's strongest state in the 1840 election.[1]

  1. ^ "1840 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.