1844 United States presidential election in Vermont

1844 United States presidential election in Vermont

← 1840 November 1 - December 4, 1844 1848 →
 
Nominee Henry Clay James K. Polk James G. Birney
Party Whig Democratic Liberty
Home state Kentucky Tennessee Michigan
Running mate Theodore Frelinghuysen George M. Dallas Thomas Morris
Electoral vote 6 0 0
Popular vote 26,780 18,049 3,970
Percentage 54.84% 36.96% 8.13%

County Results

President before election

John Tyler
Independent

Elected President

James K. Polk
Democratic

The 1844 United States presidential election in Vermont took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk and Liberty candidate James G. Birney. Clay won Vermont by a margin of 17.88%.

With 54.84% of the popular vote, Vermont would prove to be Henry Clay's second strongest state after Rhode Island. Vermont would also prove to be James G. Birney's third strongest state after New Hampshire and Massachusetts.[1]

  1. ^ "1844 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.