1856 United States presidential election in Vermont

1856 United States presidential election in Vermont

← 1852 November 4, 1856 1860 →
 
Nominee John C. Frémont James Buchanan
Party Republican Democratic
Home state California Pennsylvania
Running mate William L. Dayton John C. Breckinridge
Electoral vote 5 0
Popular vote 39,561 10,577
Percentage 77.96% 20.84%

County Results
Frémont
  60-70%
  70-80%
  80-90%


President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Vermont took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican candidate, John C. Frémont, over the Democratic candidate, James Buchanan, and the Know Nothing candidate, Millard Fillmore. Frémont won the state by a margin of 57.12%.

With 77.96% of the popular vote, Vermont would be his strongest victory in the Union in terms of percentage in the popular vote.[1]

Frémont's victory also started the 104-year-long streak of Republican presidential candidate victories in Vermont, which would last for 27 consecutive presidential elections from 1856 through 1960—as of 2020, still tied with Georgia from 1852 to 1960 for the most of any state.[2] A Democratic presidential candidate would not win Vermont until Lyndon B. Johnson won the state against Barry Goldwater 108 years later in 1964.

  1. ^ "1856 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "Will Vermont's 27-Cycle GOP Presidential Streak Ever Be Broken?". Smart Politics. April 30, 2012. Retrieved May 16, 2021.