1860 United States presidential election in Delaware

1860 United States presidential election in Delaware

← 1856 November 6, 1860 1864 →
 
Nominee John C. Breckinridge John Bell
Party Southern Democratic Constitutional Union
Home state Kentucky Tennessee
Running mate Joseph Lane Edward Everett
Electoral vote 3 0
Popular vote 7,339 3,888
Percentage 45.54% 24.13%

 
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel V. Johnson
Electoral vote 0 0
Popular vote 3,822 1,066
Percentage 23.72% 6.61%

County Results
Breckinridge
  40-50%
  50-60%


President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Delaware took place on November 6, 1860, as part of the 1860 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Delaware was won by the Southern Democratic candidate 14th Vice President of the United States John C. Breckinridge of Kentucky and his running mate Senator Joseph Lane of Oregon. They defeated the Constitutional Union candidate Senator John Bell of Tennessee and his running mate Governor of Massachusetts Edward Everett, Republican candidate Illinois Representative Abraham Lincoln and his running mate Senator Hannibal Hamlin of Maine as well as Democratic candidate 15th Senator Stephen A. Douglas of Illinois and his running mate 41st Governor of Georgia Herschel V. Johnson. Breckinridge won the state by a margin of 21.41%.

The Republicans ran a slate of electors for Lincoln, but did not nominate any candidates for other federal and state offices. The party instead endorsed the candidates of the People's Party, an anti-Democratic coalition that supported the Republican presidential ticket.[1]

  1. ^ Abbott 1986, p. 17.