1860 United States presidential election in Ohio

1860 United States presidential election in Ohio

← 1856 November 6, 1860 (1860-11-06) 1864 →
 
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel V. Johnson
Electoral vote 23 0
Popular vote 221,809 187,421
Percentage 51.24% 43.30%

County Results

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Ohio took place on November 6, 1860, as part of the 1860 United States presidential election. Voters chose 23 representatives, or electors, to the Electoral College, who voted for president and vice president.

Ohio was won by the Republican nominee Illinois Representative Abraham Lincoln and his running mate Senator Hannibal Hamlin of Maine. They defeated the Democratic nominee, Senator Stephen A. Douglas of Illinois and his running mate 41st Governor of Georgia Herschel V. Johnson. Lincoln won the state by a margin of 7.94%.

Liberty Party (under the name Union Party[1]) candidate Gerrit Smith received 136 of his 171 popular votes in Ohio alone. The other 35 votes came from Illinois.[2]

The 1860 presidential election in Ohio began a streak in which no Republican candidate won the election without carrying the state.

  1. ^ "US President - Liberty (Union) National Convention". Our Campaigns. November 24, 2008.
  2. ^ "RADICAL ABOLITION NATIONAL CONVENTION". Douglass' Monthly. October 1860. p. 352.