1864 United States presidential election in Nevada

1864 United States presidential election in Nevada

November 8, 1864 1868 →
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 2 0
Popular vote 9,826 6,594
Percentage 59.84% 40.16%


County results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

The 1864 United States presidential election in Nevada took place on November 8, 1864, as part of the 1864 United States presidential election. Nevada voters chose three electors of the Electoral College, two of whom voted for president and vice president.[1][2]

Nevada voted in its first ever presidential election in 1864, having become the 36th state just eight days before the election (on October 31). The state was won by the National Union candidate, incumbent Republican President Abraham Lincoln of Illinois and his running mate former Senator and Military Governor of Tennessee Andrew Johnson. They defeated the Democratic candidate, 4th Commanding General of the United States Army George B. McClellan of New Jersey and his running mate Representative George H. Pendleton of Ohio.[1] Lincoln won the state by a margin of 19.68%.

Due to one of the electors, Addison Peck, getting snowbound and there being no law to replace him,[2] this election is one of three occasions where only two electoral votes were cast by a state or district in a presidential election: the others were in Mississippi in 1820, as one of the state's three electors died before the Electoral College convened and there was insufficient time to find a replacement, and the District of Columbia in 2000, as one of the district's three electors abstained.

  1. ^ a b "1864 Presidential Election Results Nevada".
  2. ^ a b Rocha, Guy. "Nevada Myths". Nevada State Library and Archives. Archived from the original on September 8, 2022. Retrieved April 22, 2021.