1868 United States presidential election in Vermont

1868 United States presidential election in Vermont

← 1864 November 3, 1868 1872 →
 
Nominee Ulysses S. Grant Horatio Seymour
Party Republican Democratic
Home state Illinois New York
Running mate Schuyler Colfax Francis Preston Blair Jr.
Electoral vote 5 0
Popular vote 44,167 12,045
Percentage 78.57% 21.43%

County Results
Grant
  70-80%
  80-90%
  90-100%


President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Vermont took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 57.14%.

With 78.57% of the popular vote, Vermont would be Grant's strongest victory in terms of percentage in the popular vote.[1] In addition, Grant's performance in Vermont in popular vote percentage was the second-best for a Republican presidential candidate only after William McKinley's 80.08% in 1896. Grant's performance in Addison County is also the last time that a Republican, or any candidate, has received over 90% in a Vermont county, and one of only two occasions (along with Abraham Lincoln's performance in Addison four years earlier) that a candidate has done so despite the state's overwhelming Republican dominance for nearly a century.

  1. ^ "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.