1875 Iowa Senate election

1875 Iowa Senate election

← 1873 October 12, 1875 1877 →

30 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party Third party
 
Party Republican Democratic Anti-Monopoly
Last election 36 10 4
Seats after 40 10 0
Seat change Increase4 Steady Decrease4

     Democratic hold      Republican hold
     Democratic gain      Republican gain

In the 1875 Iowa State Senate elections, Iowa voters elected state senators to serve in the sixteenth Iowa General Assembly. Elections were held in 30 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

The general election took place on October 12, 1875.[1]

Following the previous election, Republicans had control of the Iowa Senate with 36 seats to Democrats' 10 seats and four members of the Anti-Monopoly Party.

To claim control of the chamber from Republicans, the Democrats needed to net 16 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1875 general election with the balance of power shifting to Republicans holding 40 seats and Democrats having 10 seats (a net gain of 4 seats for Republicans).

  1. ^ "General Assembly: 16 (01/10/1876 - 01/13/1878)". Iowa Legislature. Retrieved July 12, 2021.