1880 United States presidential election in Alabama|
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| Turnout | 12.03% of the total population  5.19 pp[1] |
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 County results
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Hancock
40–50%
50–60%
60–70%
70–80%
80–90%
90–100%
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Garfield
40–50%
50–60%
60–70%
80–90%
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The 1880 United States presidential election in Alabama took place on November 2, 1880, as part of the nationwide presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
Alabama was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 59.99% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee, Chester A. Arthur, with 37.10% of the vote.[2]
5.19 pp[1]
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Government