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29 out of 50 seats in the Iowa State Senate 26 seats needed for a majority | |||||||||||||||||||||||||||||||||||||||||||||||
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Elections in Iowa |
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In the 1883 Iowa State Senate elections Iowa voters elected state senators to serve in the twentieth Iowa General Assembly. Elections were held in 29 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.
The general election took place on October 9, 1883.[1]
Following the previous election, Republicans had control of the Iowa Senate with 45 seats to Democrats' two seats, two Greenbackers, and one Independent.
To claim control of the chamber from Republicans, the Democrats needed to net 24 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1883 general election with the balance of power shifting to Republicans holding 39 seats and Democrats having 11 seats (a net gain of 9 seats for Democrats).