1888 United States presidential election in Maryland

1888 United States presidential election in Maryland

← 1884 November 6, 1888 1892 →
 
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Allen G. Thurman Levi P. Morton
Electoral vote 8 0
Popular vote 106,188 99,986
Percentage 50.34% 47.40%

County Results

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Maryland took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Maryland voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a narrow margin of 2.94%. Despite the narrow margin, Maryland was still 2.11% more Democratic than the nation at large.[1]

  1. ^ "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved March 31, 2023.