1892 United States presidential election in Alabama

1892 United States presidential election in Alabama
Cleveland 40–50% 50–60% 60–70% 70–80% 80–90%	Weaver 40–50% 50–60% 60–70% 70–80%
President before election; Benjamin Harrison; Republican	Elected President ; Grover Cleveland; Democratic

The 1892 United States presidential election in Alabama took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Alabama voters chose eleven electors to the Electoral College, which selected the president and vice president.

Alabama was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois. However, Weaver performed well in the South as he won counties in Alabama, Georgia, Mississippi, North Carolina, and Texas. Populists did best in Alabama, where electoral chicanery probably carried the day for the Democrats.^[1]

^ Charles W. Calhoun (ed.), The Gilded Age: Perspectives on the Origins of Modern America. Blue Ridge Summit, PA: Rowman & Littlefield Publishers, 2006; p. 295.