1892 United States presidential election in Maryland

1892 United States presidential election in Maryland

← 1888 November 8, 1892 1896 →
 
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai Stevenson I Whitelaw Reid
Electoral vote 8 0
Popular vote 113,866 92,736
Percentage 53.39% 43.48%

County Results

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Maryland took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose eight electors to the Electoral College, which selected the president and vice president.

Maryland was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois. Democrats would not win the popular vote in Maryland again until 1912.

In this election, Maryland voted 6.9% more Democratic than the nation at-large.[1]

  1. ^ "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved April 26, 2023.