1892 United States presidential election in Montana

1892 United States presidential election in Montana

November 8, 1892 (1892-11-08) 1896 →
 
Nominee Benjamin Harrison Grover Cleveland James Weaver
Party Republican Democratic Populist
Home state Indiana New York Iowa
Running mate Whitelaw Reid Adlai Stevenson James Field
Electoral vote 3 0 0
Popular vote 18,871 17,690 7,338
Percentage 42.44% 39.79% 16.50%

County Results

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Montana took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Montana participated in its first-ever presidential election, having become the 41st state on November 8, 1889. The state voted for the Republican nominee, incumbent president Benjamin Harrison, over the Democratic nominee, former president Grover Cleveland, who was running for a second, non-consecutive term and over the People's Party (Populists) nominee James B. Weaver. Harrison won Montana by a narrow margin of 2.65%.

Cleveland is the only Democrat to win the White House without carrying Silver Bow County.