1892 United States presidential election in Wyoming

1892 United States presidential election in Wyoming

November 8, 1892 1896 →
 
Nominee Benjamin Harrison James B. Weaver
Party Republican Populist
Alliance Democratic[a]
Home state Indiana Iowa
Running mate Whitelaw Reid James G. Field
Electoral vote 3 0
Popular vote 8,454 7,722
Percentage 50.52% 46.14%

County Results

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Wyoming took place on November 8, 1892, as part of the 1892 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Wyoming participated in its first ever presidential election, having become the 44th state on July 10, 1890. The state was won by President Benjamin Harrison (RIndiana), the 28th United States Ambassador to France Whitelaw Reid, with 50.52 percent of the popular vote, against representative James B. Weaver (PIowa), running with the Attorney General of Virginia, James G. Field, with 46.14 percent of the popular vote.[1] Harrison won the state by a narrow margin of 4.38%.


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  1. ^ "1892 Presidential Election Results — Wyoming".