1895 Boston mayoral election

1895 Boston mayoral election

← 1894 December 10, 1895 1897 →
 
Candidate Josiah Quincy Edwin Upton Curtis
Party Democratic Republican
Popular vote 40,270 35,864
Percentage 52.5% 46.7%

Mayor before election

Edwin Upton Curtis
Republican

Elected mayor

Josiah Quincy
Democratic

The Boston mayoral election of 1895 occurred on Tuesday, December 10, 1895. Democratic nominee Josiah Quincy defeated Republican incumbent mayor Edwin Upton Curtis and one other contender to win election to his first term.[1]

Due to a change of the city charter in June 1895,[2] this was the first Boston mayoral election for a two-year term; prior mayoral elections had been held annually.

Quincy was inaugurated on Monday, January 6, 1896.[3] His grandfather Josiah Quincy IV (known as Josiah Quincy Jr.) and great-grandfather Josiah Quincy III also had served as Mayors of Boston.[4]

  1. ^ "QUINCY'S PLURALITY 4441". The Boston Globe. December 11, 1895. p. 1. Retrieved March 22, 2018 – via pqarchiver.com.[permanent dead link]
  2. ^ "CHARTER AMENDED". The Boston Globe. June 2, 1895. p. 1. Retrieved March 13, 2018 – via pqarchiver.com.
  3. ^ "MAYOR QUINCY'S INAUGURAL". The Boston Globe. January 7, 1896. p. 6. Retrieved March 22, 2018 – via pqarchiver.com.[permanent dead link]
  4. ^ "THE THIRD MAYOR JOSIAH QUINCY". The Boston Globe. December 11, 1895. p. 12. Retrieved March 22, 2018 – via pqarchiver.com.[permanent dead link]