1896 Washington gubernatorial election

1896 Washington gubernatorial election

← 1892 November 3, 1896 1900 →
 
Nominee John Rankin Rogers Potter C. "Charley" Sullivan
Party Populist Republican
Alliance
Popular vote 50,849 38,154
Percentage 55.55% 41.68%

Results by county
Rogers:      40–50%      50–60%      60–70%      70–80%
Sullivan:      40–50%      50–60%

Governor before election

John McGraw
Republican

Elected Governor

John Rankin Rogers
Populist

The 1896 Washington gubernatorial election was held on November 3, 1896.

Populist nominee John Rankin Rogers defeated Republican nominee Charley Sullivan, with 55.55% of the vote.[1] In this statewide election, including for all other state officers such as Lieutenant Governor, the Democrats fused with the Populists, except for the presidential election where the Democratic Party ran an independent slate of electors. This alliance would formally merge as the Democratic Party for the next election.

  1. ^ Kalb, Deborah, ed. (2009). Guide to U.S. Elections (6th ed.). Washington, DC: CQ Press. p. 1656. ISBN 9781604265361.