1900 United States presidential election in Minnesota

1900 United States presidential election in Minnesota
McKinley 40-50% 50-60% 60-70% 70-80% 80-90%	Bryan 40-50% 50-60% 60-70%
President before election; William McKinley; Republican	Elected President ; William McKinley; Republican

The 1900 United States presidential election in Minnesota took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. State voters chose nine electors to the Electoral College, which selected the president and vice president.

Minnesota was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. They defeated the Democratic nominees, former U.S. Representative and 1896 Democratic presidential nominee William Jennings Bryan and his running mate, former Vice President Adlai Stevenson I. McKinley won the state by a margin of 24.52% in this rematch of the 1896 presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.

With 60.21 percent of the popular vote, Minnesota would be McKinley's fifth strongest victory in terms of percentage in the popular vote after Vermont, North Dakota, Maine and Pennsylvania.^[1]

Bryan had previous lost Minnesota to McKinley four years earlier and would later lose the state again in 1908 to William Howard Taft.

^ "1900 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

[1] "1900 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

[1]