1900 United States presidential election in Mississippi

1900 United States presidential election in Mississippi

← 1896 November 6, 1900 1904 →
 
Nominee William Jennings Bryan William McKinley
Party Democratic Republican
Home state Nebraska Ohio
Running mate Adlai Stevenson I Theodore Roosevelt
Electoral vote 9 0
Popular vote 51,706 5,707
Percentage 87.56% 9.66%

County Results
Bryan
  60-70%
  70-80%
  80-90%
  90-100%


President before election

William McKinley
Republican

Elected President

William McKinley
Republican

The 1900 United States presidential election in Mississippi took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Voters chose nine electors to the Electoral College, which selected the president and vice president.

Mississippi was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Adlai Stevenson I of Illinois. They defeated the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. Bryan won the state by a margin of 77.9%.

With 87.56% of the popular vote, Mississippi would prove to be Bryan's second strongest state in the 1900 presidential election only after South Carolina.[1]

Bryan had previously won Mississippi against McKinley four years earlier and would later win the state again in 1908 against William Howard Taft.

  1. ^ "1900 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.