1900 United States presidential election in New Jersey

1900 United States presidential election in New Jersey

← 1896 November 6, 1900 1904 →

Nominee William McKinley William Jennings Bryan Party Republican Democratic Home state Ohio Nebraska Running mate Theodore Roosevelt Adlai E. Stevenson Electoral vote 10 0 Popular vote 221,754 164,879 Percentage 55.27% 41.10%

County Results McKinley   50-60%   60-70% Bryan   50-60%

President before election William McKinley Republican Elected President William McKinley Republican

Elections in New Jersey
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v t e

The 1900 United States presidential election in New Jersey took place on November 6, 1900. Voters chose ten representatives, or electors to the Electoral College, who voted for president and vice president.

New Jersey overwhelmingly voted for the Republican nominee, President William McKinley, over the Democratic nominee, former U.S. Representative and 1896 Democratic presidential nominee William Jennings Bryan. McKinley won New Jersey by a margin of 14.17 points in this rematch of the 1896 presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.

Bryan had previously lost New Jersey to McKinley four years earlier and would later lose the state again in 1908 to William Howard Taft. McKinley was the first Republican to carry New Jersey more than once, and the only one to do so until Dwight D. Eisenhower in 1956.