1904 United States presidential election in Alabama

1904 United States presidential election in Alabama
Parker 40–50% 50–60% 60–70% 70–80% 80–90% 90–100%	Roosevelt 50–60%
President before election; Theodore Roosevelt; Republican	Elected President ; Theodore Roosevelt; Republican

The 1904 United States presidential election in Alabama took place on November 8, 1904. All contemporary 45 states were part of the 1904 presidential election. Alabama voters chose eleven electors to the Electoral College, which selected the president and vice president.

Alabama was won by the Democratic nominees, Chief Judge Alton B. Parker of New York and his running mate Henry G. Davis of West Virginia. They defeated the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. Parker won the state by a landslide margin of 52.72%.

Due to the widespread disenfranchisement of African-Americans during the Jim Crow era, only 13 African-Americans in all of Sumter County voted in the 1904 presidential election, all thirteen of whom voted for Theodore Roosevelt and all thirteen of whom would be prevented from voting in the next several presidential elections.^[1]

With 73.37% of the popular vote, Alabama would prove to be Parker's fourth strongest state after South Carolina, Mississippi and Louisiana.^[2]

^ Lawrence, Betty. History of Sumter County, Alabama. United States: Mount Barton Publishers, 1995.
^ "1904 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

[1] Lawrence, Betty. History of Sumter County, Alabama. United States: Mount Barton Publishers, 1995.

[2] "1904 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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