1904 United States presidential election in Vermont

1904 United States presidential election in Vermont

← 1900 November 8, 1904 1908 →
 
Nominee Theodore Roosevelt Alton B. Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry G. Davis
Electoral vote 4 0
Popular vote 40,459 9,777
Percentage 77.97% 18.84%

Roosevelt
  50-60%
  60-70%
  70-80%
  80-90%
  90-100%


President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

The 1904 United States presidential election in Vermont took place on November 8, 1904, as part of the 1904 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont overwhelmingly voted for the Republican nominee, President Theodore Roosevelt and his running mate Charles W. Fairbanks of Indiana. They defeated the Democratic nominees, former Chief Judge of New York Court of Appeals Alton B. Parker and his running mate, former US Senator Henry G. Davis of West Virginia. Roosevelt won the state by a landslide margin of 59.13%.

With 77.97% of the popular vote, Vermont would be Roosevelt's strongest victory in terms of percentage of the popular vote.[1]

  1. ^ "1904 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.