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22 out of 50 seats in the Iowa State Senate 26 seats needed for a majority | |||||||||||||||||||
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| Elections in Iowa |
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The 1906 Iowa State Senate elections took place as part of the biennial 1906 United States elections. Iowa voters elected state senators in 22 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.
A statewide map of the 50 state Senate districts in the 1906 elections is provided by the Iowa General Assembly here.
The 1906 elections were the last in Iowa before primary elections were established by the Primary Election Law in 1907.[2] The general election took place on November 6, 1906.[3]
Following the previous election, Republicans had control of the Iowa Senate with 42 seats to Democrats' 8 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 18 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1906 general election with the balance of power shifting to Republicans holding 36 seats and Democrats having 14 seats (a net gain of 6 seats for Democrats).
- ^ "Jount Resolution No. 5: Biennial Elections" (PDF). Iowa General Assembly. Retrieved June 19, 2021.
- ^ "Primary Election Law" (PDF). Iowa General Assembly. Retrieved June 19, 2021.
- ^ "General Election 1906 For State Senator" (PDF). Iowa Official Register. Retrieved June 19, 2021.
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