1908 United States presidential election in Wyoming

1908 United States presidential election in Wyoming

← 1904 November 3, 1908 1912 →
 
Nominee William Howard Taft William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate James S. Sherman John W. Kern
Electoral vote 3 0
Popular vote 20,846 14,918
Percentage 55.43% 39.67%

County Results
Taft
  40-50%
  50-60%
  60-70%


President before election

Theodore Roosevelt
Republican

Elected President

William Howard Taft
Republican

The 1908 United States presidential election in Wyoming took place on November 3, 1908, as part of the 1908 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Wyoming was won by the Secretary of War William Howard Taft (ROhio), running with representative James S. Sherman, with 55.43 percent of the popular vote, against representative William Jennings Bryan (DNebraska), running with Senator John W. Kern, with 39.67 percent of the popular vote.[1] Taft won the state by a margin of 15.76%.

Bryan had previously won Wyoming against William McKinley in 1896 but had lost the state to McKinley in 1900.

  1. ^ "1908 Presidential Election Results Wyoming".